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Angles in a Triangle — Properties, Types, and Sum Rule

Grade: 7–8 | Topic: Geometry

What You Will Learn

By the end of this page, you will know that the three interior angles of any triangle sum to 180°, be able to find any missing angle given the other two, classify triangles by their angles, and use the exterior angle theorem.

Theory

The Triangle Angle Sum Property

The three interior angles of any triangle always add up to exactly 180°.

A+B+C=180°\angle A + \angle B + \angle C = 180°

This means: if you know any two angles, you can always find the third by subtracting from 180°.

Why 180°? If you draw a straight line through a triangle's vertex parallel to the opposite side, the three angles at that vertex form a straight line — which is exactly 180°.

Types of Triangles by Angles

TypeAngle property
Acute triangleAll three angles <90°< 90°
Right triangleExactly one angle =90°= 90°
Obtuse triangleExactly one angle >90°> 90°
Equilateral triangleAll angles =60°= 60°

The Exterior Angle Theorem

An exterior angle is formed by extending one side of a triangle beyond the vertex. It equals the sum of the two non-adjacent interior angles (also called remote interior angles).

Exterior angle=A+B\text{Exterior angle} = \angle A + \angle B

where A\angle A and B\angle B are the two interior angles not next to the exterior angle.

Special Triangle Properties

Isosceles triangle: two equal sides → the two base angles (angles opposite the equal sides) are also equal.

Equilateral triangle: all three sides equal → all three angles are 60°60°.

Right triangle: one angle is 90°90° → the other two angles are complementary (they add up to 90°90°).

Worked Examples

Example 1: Finding a Missing Angle

Problem: A triangle has angles of 47°47° and 68°68°. Find the third angle.

Step 1: Use the angle sum property. C=180°47°68°\angle C = 180° - 47° - 68°

Step 2: Calculate. C=180°115°=65°\angle C = 180° - 115° = 65°

Answer: The third angle is 65°\mathbf{65°}.


Example 2: Isosceles Triangle

Problem: An isosceles triangle has a vertex angle of 40°40°. Find the two base angles.

Step 1: The two base angles are equal. Let each base angle =x= x.

Step 2: Apply the angle sum. 40°+x+x=180°40° + x + x = 180° 2x=140°2x = 140° x=70°x = 70°

Answer: Each base angle is 70°\mathbf{70°}.


Example 3: Using the Exterior Angle Theorem

Problem: Two interior angles of a triangle are 52°52° and 74°74°. Find the exterior angle at the third vertex.

Step 1: The exterior angle equals the sum of the two non-adjacent interior angles. Exterior angle=52°+74°=126°\text{Exterior angle} = 52° + 74° = 126°

Verify: The third interior angle =180°52°74°=54°= 180° - 52° - 74° = 54°. The exterior angle =180°54°=126°= 180° - 54° = 126°. Consistent.

Answer: The exterior angle is 126°\mathbf{126°}.


Example 4: Algebraic Angle Problem

Problem: The angles of a triangle are xx, 2x2x, and 3x3x. Find each angle and classify the triangle.

Step 1: Set up the equation. x+2x+3x=180°x + 2x + 3x = 180° 6x=180°6x = 180° x=30°x = 30°

Step 2: Find each angle. x=30°,2x=60°,3x=90°x = 30°, \quad 2x = 60°, \quad 3x = 90°

Step 3: Classify. One angle is exactly 90°90° — this is a right triangle.

Answer: Angles are 30°30°, 60°60°, 90°90° — a right triangle.

Common Mistakes

Mistake 1: Setting Angles Equal to 90° Instead of 180°

A+B+C=90°\angle A + \angle B + \angle C = 90°

✅ The angles of a triangle sum to 180°180°, not 90°90°. (Two complementary angles sum to 90°90°, but that is only for a pair of angles, not a triangle.)

Mistake 2: Using the Exterior Angle as an Interior Angle

❌ An exterior angle of 110°110° is used as one of the triangle's interior angles.

✅ The exterior angle is outside the triangle. The interior angle at that vertex is 180°110°=70°180° - 110° = 70°.

Mistake 3: Assuming All Triangles Can Have Two Obtuse Angles

❌ A triangle with angles 100°100°, 95°95°, and an unknown third angle.

100°+95°=195°>180°100° + 95° = 195° > 180°, which is impossible. A triangle can have at most one obtuse angle.

Practice Problems

Try these on your own before checking the answers:

  1. A triangle has angles 33°33° and 91°91°. Find the third angle and classify the triangle.
  2. An equilateral triangle has one angle labelled (2x+10)°(2x + 10)°. Find xx.
  3. Two angles of a triangle are xx and 3x3x. The third angle is 60°60°. Find xx.
  4. An exterior angle of a triangle measures 135°135°. One of the non-adjacent interior angles is 80°80°. Find the other non-adjacent interior angle.
  5. Can a triangle have angles of 90°90°, 90°90°, and 0°? Explain.
Click to see answers
  1. 180°33°91°=56°180° - 33° - 91° = 56°. Triangle has an angle >90°> 90° (the 91°91° angle), so it is an obtuse triangle.
  2. Each angle of an equilateral triangle =60°= 60°. So 2x+10=60    2x=50    x=252x + 10 = 60 \implies 2x = 50 \implies x = 25.
  3. x+3x+60°=180°    4x=120°    x=30°x + 3x + 60° = 180° \implies 4x = 120° \implies x = 30°. Angles: 30°30°, 90°90°, 60°60°.
  4. Exterior angle == sum of non-adjacent angles: 135°=80°+other    other=55°135° = 80° + \text{other} \implies \text{other} = 55°.
  5. No. 90°+90°+0°=180°90° + 90° + 0° = 180° mathematically, but a triangle cannot have a 0° angle (a side would collapse to a point). Triangles must have three positive interior angles.

Summary

  • The three interior angles of any triangle sum to 180°180°.
  • To find a missing angle: subtract the known angles from 180°180°.
  • Exterior angle theorem: exterior angle = sum of the two non-adjacent interior angles.
  • Triangle types: acute (all <90°< 90°), right (one =90°= 90°), obtuse (one >90°> 90°), equilateral (all =60°= 60°).

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